Question:
if xcube xsquare-ax b is divisible by xsquare-x,write the values of a and b
Answer:
Let f(x) = x3 + x2 - ax + b
Given it is exactly divisible by x2 - x
So, x2 - x = 0
=> x(x - 1) = 0
=> x = 0, 1
Case 1. x = 0
=> f(0) = 0
=> 03 + 02 - a*0 + b = 0
=> b = 0
Case 2. x = 1
=> f(1) = 0
=> 13 + 12 - a*1 + b = 0
=> 1 + 1 - a + b = 0
=> 2 - a + b = 0
=> 2 - a + 0 = 0
=> 2 - a = 0
=> a = 2
So, the value of a is 2 and b is 0
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