Book a personalised 1:1 class with LearnoHub
Search
Given, 1 is a zero of polynomial P(x) = ax2 - 3(a - 1) - 1
Put x = 1 in the equation, we get
P(1) = 0
=> a*12 - 3(a - 1) - 1 = 0
=> a - 3a + 3 - 1 = 0
=> -2a + 2 = 0
=> 2a = 2
=> a = 2/2
=> a = 1
So, the value of a is 1