Question:
If the polynomial 6x4 8x3 17x2 21x 7 is divided by another polynomial 3x2 4x 1, the remainder comes out to be (ax b), find a and b.
Answer:
When we divide 6x4 + 8x3 + 17x2 + 21x + 7 by the polynomial 3x2 + 4x + 1, we get
Quetient = 3x2 + 4x + 5
and Remainder = x + 2
Given, remainder = ax + b
On comparing, we get
a = 1 and b = 2
So, the value of a is 1 and b is 2
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