

Given, x + a is a factor of the the polynomial 2x2 + 2ax + 5x + 10
Since x + a is a factor, so it will satisfy the above polynomial.
Now, put x + a = 0
=> x = -a in the polynomial, we get
2(-a)2 + 2a(-a) + 5*(-a) + 10 = 0
=> 2a2 - 2a2 - 5a + 10 = 0
=> -5a + 10 = 0
=> 5a = 10
=> a = 10/5
=> a = 2
So, the value of a is 2
