Question:
Find all other zeroes of the polynomial p(x) = 2x3 3x2 – 11x – 6, if one of its zero is –3.
Answer:
Given, polynomial p(x) = 2x3 + 3x2 – 11x – 6
Given one of the zero is -3
So, x = -3
=> x + 3 = 0
When we divide 2x3 + 3x2 – 11x – 6 by x + 3, we get
Quotient = 2x2 – 3x – 2
Now, 2x2 – 3x – 2 = 0
=> 2x2 – 4x + x – 2 = 0
=> 2x(x - 2) + 1(x - 2) = 0
=> (x - 2)*(2x + 1) = 0
=> x = 2, -1/2
So, the other zeroes are 2 and -1/2
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