Question:
.If the square of the difference of the zeros of the quadratic polynomial f(x)=x square plus px plus45 is equal to 144, find the value of p
Answer:
Given quadratic polynomial is f(x) = x2 + px + 45
Let a and b is the zeroes of the quadratic polynomial
So, a + b = -p and a*b = 45
Given, (a - b)2 = 144
=> (a + b)2 - 4a*b = 144
=> (-p)2 - 4*45 = 144
=> p2 - 180 = 144
=> p2 = 180 + 144
=> p2 = 324
=> p = ±√324
=> p = ±18
So, the value of p is ±18
Not what you are looking for? Go ahead and submit the question, we will get back to you.
