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Question:
when the ages will be as old as father today their ages will add up to 126 years.when the father as old as son is today,their ages add up to 38 years.Find their present ages
Answer:

Let the present age of son = x

and the present age of father = y

Difference in their ages = y - x

Given, when the ages will be as old as father today their ages will add up to 126 years

=> {x + (y - x)} + {y + (y - x)} = 126

=> {x + y - x} + {y + y - x} = 126

=> y + 2y - x = 126

=> 3y - x = 126       .................1

Again, when the father as old as son is today, their ages add up to 38 years

=> {y + (x - y)} + {x + (x - y)} = 38

=> {y + x - y} + {x + x - y} = 38

=> x + 2x - y = 38

=> 3x - y = 38       .................2

Multiply by 3 in equation 2, we get

=> 9x - 3y = 114   ..............3

Add equation 1 and 3, we get

    8x = 240

=> x = 240/8

=> x = 30

From equation 1, we get

    3y - 30 = 126

=>3y = 126 + 30

=> 3y = 156

=> y = 156/3

=> y = 52

So, the present age of son = x = 30 years

and the present age of father = y = 52 years

 

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