Question:
The sum of the digits of a two-digit number is 12.The number obtained by interchanging its digits exceeds the given number by 18,find the number
Answer:
Let the digit in the number is xy.
So number is 10x + y
Given
sum of the digits of a two-digit number is 12
=> x+ y = 12..........................1
Again
10y + x = 10x+ y +18
=> 10y + x - 10x - y = 18
=> 9y -9x = 18
=> y - x = 2 ..................2
Solving equation 1 and 2, we get
x = 5, y = 7
So the number is 57.
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