Question:
The sum of the digit of two digit no is 8 and the difference btw the no and that formed by reversing the digits is 18
Answer:
Let the unit digit and 10s digit of the number is x and y respectively.
So, the number = 10y + x
When we reverse the number, then the number = 10x + y
Now, according to question, we have
x + y = 8 .........1
and (10y + x) - (10x + y) = 18
=> 10y + x - 10x - y = 18
=> 9y - 9x = 18
=> 9(y - x) = 18
=> y - x = 18/9
=> y - x = 2 ...........2
Add equation 1 and 2, we get
2y = 8 + 2
=> 2y = 10
=> y = 10/2
=> y = 5
From equation 1, we get
x + 5 = 8
=> x = 8 - 5
=> x = 3
Hence, the number = 10y + x = 10*5 + 3 = 50 + 3 = 53
So, the required number = 53
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