learnohub
Question:
Solve: 47x + 31y = 63, 31x + 47y = 15.
Answer:

Given,

47x + 31y = 63    ...............1

31x + 47y = 15    ...............2

Multiply equation 1 by 31 and equation 2 by 47, we get

47 * 31x + 31 * 31y = 63*31    ...............3

31 * 47x + 47 * 47y = 15*47    ...............4

Subtraction equation 3 by 4, we get

    (47 * 31x + 31 * 31y) - (31 * 47x + 47 * 47y) = 63*31 - 15*47

=> 47 * 31x + 31 * 31y - 31 * 47x - 47 * 47y = 63*31 - 15*47

=>  31 * 31y - 47 * 47y = 63*31 - 15*47

=> 961y - 2209y = 1953 - 705

=> -1248y = 1248

=> y = -1248/1248

=> y = -1

From equation 1, we get

     47x + 31 * (-1) = 63

=> 47x - 31 = 63

=> 47x = 63 + 31

=> 47x = 94

=> x = 94/47

=> x = 2

Hence, x = 2, y = -1

Not what you are looking for? Go ahead and submit the question, we will get back to you.

learnohub

Classes

  • Class 6
  • Class 7
  • Class 8
  • Class 9
  • Class 10
  • Class 11
  • Class 12
  • ICSE 6
  • ICSE 7
  • ICSE 8
  • ICSE 9
  • ICSE 10
  • NEET
  • JEE

YouTube Channels

  • LearnoHub Class 11,12
  • LearnoHub Class 9,10
  • LearnoHub Class 6,7,8
  • LearnoHub Kids

Overview

  • FAQs
  • Privacy Policy
  • Terms & Conditions
  • About Us
  • NGO School
  • Contribute
  • Jobs @ LearnoHub
  • Success Stories
© Learnohub 2026.