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Question:
Question 2: If tan θ = a/b , then a sin θ + b cos θ / a sin θ - b cos θ is equal to
Answer:

Given,

tan θ = a/b ,

Now, (a sin θ + b cos θ)/(a sin θ - b cos θ)

= (a sin θ/cos θ + b cos θ/cos θ)/(a sin θ/cos θ - b cos θ/cos θ)  {divide cos θ in numerator and denominator}

= (a tan θ + b)/(a tan θ - b)

= {a* a/b + b)/(a* a/b - b)

= {a2 /b + b)/(a2 /b - b)

= {(a2 + b2 )/b}/{(a2 - b2 )/b}

= (a2 + b2 )/(a2 - b2 )

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