Question:
Introduction to trigonometry part 3, there is a question find tan P cot R...in that sum..to find QR we take QR= root of PR square - QR square..here why do we subtract
Answer:
Given, PQR is a right angle triangle, right angle at Q
Now, form Pythagoras Theorem,
(PR)2 = (PQ)2 + (QR)2
=> (13)2 = (12)2 + (QR)2
=> 169 = 144 + (QR)2
=> (QR)2 = 169 - 144
=> (QR)2 = 25
=> QR = √(25)
=> QR = 5
Now, tan P = QR/PQ
=> tan P = 5/12
and cot R = QR/PQ
=> cot R = 5/12
Now, tan P - cot R = 5/12 - 5/12 = 0
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