Question:
In a triangle right angled at ang.B. How to find Sin B
Answer:
Let ABC is a right angle triangle at angle B.
The side which is in front of an angle is perpendicular.
Again the side at which angle is placed is the base and the remaining third side is hypotenuses.
So for angle B,
hypotenuse = AB
Base = BC
Perpendicluar = AC
Now sinB = AC/AB
Not what you are looking for? Go ahead and submit the question, we will get back to you.
