Question:
If 3 tan A = 4, then find sinA and cosA.
Answer:
Given, 3 tan A = 4
=> tan a = 4/3
In triangle ABC,
From Pythagoras Theorem,
BC2 = AB2 + AC2
=> AC2 = 42 + 32
=> AC2 = 16 + 9
=> AC2 = 25
=> AC = √25
=> AC = 5
Now, sin A = AB/BC = 4/5
and cos A = AC/BC = 3/5
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