Question:
find the point on x axis which is equidistant from (2,-5) and (-2,9)
Answer:
Let the point on x-axis is (x, 0)
Now √{(2-x )2 + (-5-0 )2 } = √{(-2-x )2 + (-9-0 )2 }
= (2-x )2 + (-5-0 )2 = (-2-x )2 + (-9-0 )2
= (2-x )2 + (-5)2 = (-2-x )2 + (-9)2
= 4 + x2 - 4x + 25 = 4 + x2 + 4x + 81
= - 4x + 25 = 4x + 81
=> 4x + 4x = 25 - 81
=> 8x = -56
=> x = -56/8
=> x = -7
So, the point is (-7, 0)
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