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Question:
distance between (5,2p) and (2,0) is 5 find the value of p
Answer:

Distance between (5, 2p) and (2, 0) = 5

=> √[(5-2)2 + (2p)2] = 5

=> √[32 + (2p)2 ] = 5

=> √[9 + 4p2 ] = 5

=> 9 + 4p2 = 52

=> 9 + 4p2 = 25

=> 4p2 = 25 - 9

=> 4p2 = 16

=> p2 = 16/4

=> p2 = 4

=> p = √4

=> p = 2, -2

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