Question:
Question 5: If P is a point on x-axis such that its distance from the origin is 3 units, then the coordinates of a point Q on OY such that OP = OQ, are
Answer:
Let P (x, 0) and Q(0, y) are the points on x-axis and y-axis respectively.
Given OP = 3
=> √{(x - 0)2 + (x - 0)2 } = 3
=> √x2 = 3
=> x = ±3
Now OP = OQ
=> √{(x - 0)2 + (x - 0)2 } = √{(0 - 0)2 + (y - 0)2 } =
=> ±3 = √y2
=> y = ±3
So, the coordinate of points P and Q are (±3, 0) and (0, ±3) respectively.
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