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Question:
If x:y=2:3, Then (4x-y):(2x 3y)=?
Answer:

Given x:y = 2:3

=> x/y = 2/3

Now  (4x-y):(2x+3y) = (4x-y)/(2x+3y)

                               = y*[4(x/y) - 1]/(y*[2(x/y) + 3])

                               = [4(x/y) - 1]/[2(x/y) + 3])

                               = [4(2/3) - 1]/[2(2/3) + 3]

                               = [8/3 - 1]/[4/3 + 3]

                               = [(8-3)/3]/[(4+9)/3]

                               = [5/3]/[13/3]

                               = 5/13

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