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Given x:y = 2:3
=> x/y = 2/3
Now (4x-y):(2x+3y) = (4x-y)/(2x+3y)
= y*[4(x/y) - 1]/(y*[2(x/y) + 3])
= [4(x/y) - 1]/[2(x/y) + 3])
= [4(2/3) - 1]/[2(2/3) + 3]
= [8/3 - 1]/[4/3 + 3]
= [(8-3)/3]/[(4+9)/3]
= [5/3]/[13/3]
= 5/13