Question:
Find the equation of the perpendicular dropped from the point P(5, 4) to the line joining A(2, -3) and B(4, -3)
Answer:
Equation of the line joining A(2, -3) and B(4, -3) is
(y + 3) = {(-3 + 3)/(4 - 2)}*(x - 2)
=> y + 3 = 0
=> y = -3
So, the slope m = 0
If two lines are perpendiculat to each other, then
m1 *m2 = -1
=> m2 = -1/0
=> m2 = ∞
=> m2 = 1/0
Now slope of the equation of the perpendicular dropped from the point P(5, 4) m2 = 1/0
So, the eqaution is
(y - 4) = m2 *(x - 5)
(y - 4) = (x - 5)/0
=> x - 5 = 0
This is the required equation.
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