Question:
Let ABC be a right triangle in which AB=6cm ,BC=8cm and angle B= 90 degree. BD is the perpendicular from B on AC. The circle through B C, D is drawn. Construct the tangents from A to this circle.
Answer:
Construction:
1. Draw a line segment AB = 6 cm
2. Make a right angle at point B and draw BC = 8 cm
3. Draw a perpendicular BD to AC
4. We know that in a right triangle, hypotenuse is the diameter of circumcircle.
5. Taking BC as diameter, draw a circle which passes through points B, C and D.
6. Join A to O and taking AO as diameter, draw second circle.
7. From point A, draw tangents AB and AP
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