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Question:
How to construct similar triangle with compass
Answer:

Similar Triangles:

If Two triangles ∆ABC and ∆PQR are said to be similar, following two conditions are

satisfied:

1. The corresponding angles of the triangles are equal.

i.e.,

∠A = ∠P, ∠B = ∠Q, ∠C = ∠R

and

2. Since ∆ABC and ∆PQR are two similar triangles, their corresponding sides are in a ratio

or proportion.

i.e.,

AB/PQ = BC/QR = AC/PR

We write ∆ABC and ∆PQR are similar as ∆ABC ~ ∆PQR

Construction of Similar Triangles:

The steps of construction of similar triangles are as follows 

1. Draw a ray BX which makes the acute angle with BC on the opposite side of vertex A.

2. Locate 5 points on the ray BX and mark them as B1 , B2 , B3 , B4 and B5 such that

BB1 , B1 B2 , B2 B3 , B3B4 and B4 B5 such

3. Join B5 C

4. Draw a line parallel to B5 C through B3 [Since 3 is the smallest among 3 and 5] and

mark C1 where it intersects with BC.

5. Draw a line through the point C1 parallel to AC and mark A1 where it intersects AB.

Hence, A1 B C1 is the required triangle.

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