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Question:
Prove that the tangents at any point of a circle is perpendicular to the radius through the point of contact.
Answer:

Let us suppose that there is a circle having radius OP.

Let there is a tangent AB Which touches the circle.

Now Take a point Q on line AB and join with O. 

Here OQ is greater than OP. 

Now every point on the line AB like Q1 , Q2 , Q3 ,...

OQ1 > OP

OQ2 > OP

OQ3 > OP

and so on.

So OP is the shortest distance Between the point P and line Segment AB.

Hence OP is perpendicular to AB.

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