Question:
A chord of a circle of radius 10 cm subtends a right angle at its centre. Calculate the length of the chord.
Answer:
From right angle triangle BOC,
BC2 = OB2 + OC2
=> BC2 = (10)2 + (10)2
=> BC2 = 100 + 100
=> BC2 = 200
=> BC = √200
=> BC = √(100*2)
=> BC = 10√2
So, the length of the chord is 10√2 cm
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