

Let a is the first term and d is the common difference of the AP
Given T27 - T23 = 64
=> {a + (27 - 1)d} - {a + (23 - 1)d} = 64 {since Tn = a + (n - 1)d}
=> (a + 26d) - (a + 22d) = 64
=> a + 26d - a - 22d = 64
=> 4d = 64
=> d = 64/4
=> d = 16
So, the common difference of AP is 16
