

Let us take example of an auditorium and find the sum of AP.
Let l denotes the number of seats in the last of nth row.
Now, there are n rows. The front row has a seats. The last row has l seats.
Let S denotes the total number of seats.

Now, copy the diagram, turmit upside and place it next to the given diagram.

Two copies of the auditorium produces a figure consisting of n rows each having a + l seats.
Id S is the sum of the seats in the auditorium,
Then 2S = n(a + l)
=> S = (n/2) * (a + l) ..........1
If the last row is the nth row, then
l = a + (n - 1)d
From equation 1, we get
=> S = (n/2) * {a + a + (n - 1)d}
=> S = (n/2) * {2a + (n - 1)d}
This gives the sum of n terms of the an AP.
