
Given that each element of a second order determinant is either 0 or 1.
So total number of determinants of second order with each element with 0 and 1 = 24 = 16
The value of determinant is positive in 3 cases i.e.
|1 0| |1 1| |1 0|
|0 1| |0 1| |1 1|
So required probability= 3/16