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Question:
how many 176 ohm resistors are required to carry 5A on a 220V line
Answer:

For, X number of resistors of resistance 176 Ω,

Here Supply voltage, V = 220 V

Current, I = 5 A

Equivalent resistance of the combination = R, given as

 

1/R = X x (1/176)

Or, R = 176/X

 

From Ohms Law

 

V/I = 176/X

 

Or, X = 176 x I/V = 176 x 5/220 = 4

 

So Four resistor of 176 Ω are required to draw the given amount of current.

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