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Question:
how should we prove that 3 2root5 is irrational i didnt understand this question help mee
Answer:

First we, have to prove that √5 is an irrational number.

Let us suppose that √5 is a rational number.

So √5 = p/q

=> 5 = p2 /q2

=>5q2 = p2 ..............1

So p2 is divisible by 5.

=> p is divisible by 5.

Let p =5x  (x is a positive integer)

Now p2  = 25c2

from equation 1

5q2 = 25c2

=> q2 = 5c2

So q is divisible by 5

Thus p and q has a common factor 5. It is contradiction of our assumption.

So, √5 is not a rational number.

Therefore, √5 is an irrational number.

Since, √5 is an irrational number.

Hence, 3 + 2√5 is also an irrational number.

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